Math, asked by indian8244, 1 year ago

2cos^2 x + root 2 sinx = 2

Answers

Answered by Anonymous

2

Answer:

2cos^2 x +√2 sinx -2 =0

2- 2sin^2 x + √2 sinx -2 = 0

√2sin^2x - sinx =0

sinx ( √2 sinx -1) =0

sinx =0, 1/√2

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