Math, asked by arushisaini1530, 1 year ago

2cos²60° tan²28° tan²62°

Answers

Answered by Anonymous
3
2Cos^260×tan^2(28)×tan^2(62)

2(1/2)^2×tan^2 (28)×cot^2(90-62)

2×(1/4)× tan^2(28)×cot^2(28)

(1/2)×tan^2(28)×1/tan^2(28)

1/2×1=1/2

hope it help you dear....


arushisaini1530: Thnxu....
joshuachenn2003: Good answer.
Answered by Anonymous
0

Answer:

Step-by-step explanation:

2Cos^260×tan^2(28)×tan^2(62)

2(1/2)^2×tan^2 (28)×cot^2(90-62)

2×(1/4)× tan^2(28)×cot^2(28)

(1/2)×tan^2(28)×1/tan^2(28)

1/2×1=1/2

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