Question

2cos²60° tan²28° tan²62°

Answer 1

2Cos^260×tan^2(28)×tan^2(62)

2(1/2)^2×tan^2 (28)×cot^2(90-62)

2×(1/4)× tan^2(28)×cot^2(28)

(1/2)×tan^2(28)×1/tan^2(28)

1/2×1=1/2

hope it help you dear....

Answer 2

Answer:

Step-by-step explanation:

2Cos^260×tan^2(28)×tan^2(62)

2(1/2)^2×tan^2 (28)×cot^2(90-62)

2×(1/4)× tan^2(28)×cot^2(28)

(1/2)×tan^2(28)×1/tan^2(28)

1/2×1=1/2