2cos2A=√3, A is an
acute angle, find sin 3 A
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Answer:
Sin 3A = 1/√2
Step-by-step explanation:
We have,
2Cos 2A = √3
Now,
2Cos 2A = √3
Cos 2A = √3/2
But we know that,
Cos 30° = Cos 2A
Since the angles are equal,
2A = 30°
A = 30°/2
A = 15°
Now, we must find,
Sin 3A
So,
Sin 3A = Sin 3(15°)
Sin 45° = 1/√2
Hence,
Sin 3A = 1/√2
Hope it helped and believing you understood it...All the best
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