2d+3e+5f= -9, 3d+2e - 2f=3, -3d-2e=1
Can anyone help me to solve this problem.
Answers
Answer:
Given :-
The length is 3 times of its breadth of a rectangle and the perimeter is 200 cm.
To Find :-
What is the length and breadth of a rectangle.
Formula Used :-
{\red{\boxed{\small{\bold{Perimeter\: of\: Rectangle =\: 2(Length + Breadth)}}}}}
PerimeterofRectangle=2(Length+Breadth)
Solution :-
Let, the breadth of a rectangle be x cm
And, the length of a rectangle will be 3x cm
Given :
Length = 3x cm
Breadth = x cm
According to the question by using the formula we get,
⇒ \sf 2(3x + x) =\: 2002(3x+x)=200
⇒ \sf 6x + 2x =\: 2006x+2x=200
⇒ \sf 8x =\: 2008x=200
⇒ \sf x =\: \dfrac{\cancel{200}}{\cancel{8}}x=
8
200
➠ \sf\bold{\purple{x =\: 25\: cm}}x=25cm
Hence, the required length and breadth are,
✧ Breadth = x = 25 cm
✧ Length = 3x = 3 × 25 = 75 cm
\therefore∴ The length and breadth of a rectangle is 75 cm and 25 cm respectively.
\begin{gathered}\\\end{gathered}
VERIFICATION :-
↦ \sf 2(3x + x) =\: 2002(3x+x)=200
↦ \sf 6x + 2x =\: 2006x+2x=200
By putting x = 25 we get,
↦ \sf 6(25) + 2(25) =\: 2006(25)+2(25)=200
↦ \sf 150 + 50 =\: 200150+50=200
↦ \sf\bold{200 =\: 200}200=200
➦ LHS = RHS
Hence, Verified ✔