Math, asked by devendu, 7 months ago

(2e + 3f)² + 8(2e + 3f) + 15 factorise
pls answer I will mark u as brainliest

Answers

Answered by mdnafish976
0

Answer:

(2e+3f +5)((2e+3f+3)

Step-by-step explanation:

let (2e+3f)=x

therefore

(2e + 3f)² + 8(2e + 3f) + 15 becomes

=x²+8x+15

using middle term factor

=x²+(5+3)x+15

=x²+5x+3x+15

=x(x+5) +3(x+5)

=(x+5)(x+3)

Now

substituting the value of x we get,

(2e+3f +5)((2e+3f+3) Ans

Answered by hemanth229
0

Answer:

(2e+3f+5)(2e+3f+3)=o

Step-by-step explanation:

Take 2e+3f=x

Then x. x+8x+15=0

Factorise the above equation

x. x+5x+3x+15=0

x(x+5)+3(x+5)=0

(x+5)(x+3)=0--------->(1)

put x value in above equation (1)

x=-5;x=-3

2e+3f+5=o ; 2e+3f+3=0

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