(2e + 3f)² + 8(2e + 3f) + 15 factorise
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Answers
Answered by
0
Answer:
(2e+3f +5)((2e+3f+3)
Step-by-step explanation:
let (2e+3f)=x
therefore
(2e + 3f)² + 8(2e + 3f) + 15 becomes
=x²+8x+15
using middle term factor
=x²+(5+3)x+15
=x²+5x+3x+15
=x(x+5) +3(x+5)
=(x+5)(x+3)
Now
substituting the value of x we get,
(2e+3f +5)((2e+3f+3) Ans
Answered by
0
Answer:
(2e+3f+5)(2e+3f+3)=o
Step-by-step explanation:
Take 2e+3f=x
Then x. x+8x+15=0
Factorise the above equation
x. x+5x+3x+15=0
x(x+5)+3(x+5)=0
(x+5)(x+3)=0--------->(1)
put x value in above equation (1)
x=-5;x=-3
2e+3f+5=o ; 2e+3f+3=0
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