Question

2H2(g) + O2(g) → 2H2O(g)
How many liters of H2 are required to form 5 moles of H2O at STP?
A) 11.2 liters
B) 22.4 liters
C) 44.8 liters
D) 112 liters

Answer 1

Answer:

D)112 liters

Explanation:

The mole ratio here is 1:1, so it will take 5 moles of H2 to produce 5 moles of H2O. Since all the gases occupy 22.4 liters at STP, the volume of H2 required is 22.4 moles/liter X 5 moles =112 liters.

Answer 2

The correct option regarding the amount of hydrogen gas required to form 5 moles of water at STP is D) 112l.

Given:

An equation: 2H2(g) + O2(g) → 2H2O(g)

To Find:

The amount of hydrogen gas required to form 5 moles of water at STP.

Solution:

To find the amount of hydrogen gas required to form 5 moles of water at STP we will follow the following steps:

As we know,

2 moles of hydrogen are reacted to give 2 moles of water so, their molar ratio is the same.

Now,

5 moles of hydrogen will be required to form 5 moles of water.

Also,

1 mole of any substance at STP = 22.4l

So,

Amount of 5 moles of hydrogen at STP =

$5 \: moles \: = 5 \times 22.4 = 112l$

Henceforth, the correct option regarding the amount of hydrogen gas required to form 5 moles of water at STP is D) 112l.

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