Question

(2i÷1+i)^2=
a=1
b=2i
c=1-i
d=1-2i​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

Option B is correct.

Step-by-step explanation:

As we know that

${i}^{2} = - 1$

So

${\bigg( \frac{2i}{1 + i} }\bigg)^{2} \\ \\ = > \frac{ {(2i)}^{2} }{ {(1 + i)}^{2} } \\ \\ = > \frac{4 {i}^{2} }{1 + 2i + {i}^{2} } \\ \\ = > \frac{4 ( - 1) }{1 + 2i - 1} \\ \\ = > \frac{ - 4}{2i} \\ \\ = > \frac{ - 2}{i} \\ \\ = > \frac{ - 2}{i} \times \frac{i}{i} \\ \\ = > \frac{ - 2i}{ {i}^{2} } \\ \\ = > \frac{ - 2i}{ - 1} \\ \\ {\bigg( \frac{2i}{1 + i} }\bigg)^{2} = > 2i$