2k+1,16 and 9k-2 is A.P k=?
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Answered by
3
if these terms are in AP then 16-(2k+1)=9k-2-(16)
why solving we get k is equals. to 3.
why solving we get k is equals. to 3.
Answered by
4
2k + 1, 16, 9k - 2 are in A. P.
Then, their common difference will be equal.
16 - ( 2k+1 ) = 9k - 2 - 16
16 - 2k - 1 = 9k - 18
15 - 2k = 9 k - 18
15 + 18 = 9k + 2k
11k = 33
k = 33/ 11
k = 3
Then, their common difference will be equal.
16 - ( 2k+1 ) = 9k - 2 - 16
16 - 2k - 1 = 9k - 18
15 - 2k = 9 k - 18
15 + 18 = 9k + 2k
11k = 33
k = 33/ 11
k = 3
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