(2k+1), (4k+3), (BX+ 1) are 3 consecutive terms of an AP, find the value of K and the 18term of this sequence
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1
Answer:
the 18th term of this sequence is 5
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0
Answer:
For the example
Step-by-step explanation:
Since these terms are consecutive terms of an A.P., the middle term must be the average of the other two.
⇒(k−3)+(4k+3)=2(2k+1)
⇒5k=4k+2
⇒k=2
Thus, the required value of k is 2.
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