Math, asked by mrudul44, 4 months ago

(2k+1), (4k+3), (BX+ 1) are 3 consecutive terms of an AP, find the value of K and the 18term of this sequence​

Answers

Answered by MRMODERATE
1

Answer:

the 18th term of this sequence is 5

Answered by rajvermaup1990
0

Answer:

For the example

Step-by-step explanation:

Since these terms are consecutive terms of an A.P., the middle term must be the average of the other two.

⇒(k−3)+(4k+3)=2(2k+1)

⇒5k=4k+2

⇒k=2

Thus, the required value of k is 2.

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