Question

2k, 3k-1,8 in ap find the value of k

Answer 1

Answer:

1

Step-by-step explanation:

in an ap

d1=d2=d3

d1=a2-a1

d2=a3-a2

d1=d2

2k=3k-1

3k-2k=1

k=1

Answer 2

Answer:

A1 = 2K

A2 = 3K−1

A3 = 8

D1 = D2

A2−A1= A3−A2

3K−1−2K= 8−(3K−1)

K−1= 8−3K+1

K+3K=8+1+1

4K=10

K= 10/4

K=2.5

we get, K=2.5

HOPE ITS HELPFUL