2kg mass kept on a horizontal table is acted upon by a force of 5 Newton at an angle of 60° from horizontal and moved through a distance of 3 m on the table the work done on the body is
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hey mate
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M=2kg
F=horizontal component of given force=fcos60°=5/2N
s=3m
Work done=FS cos 0°=5/2×3=7.5N
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