2KMnO4 + 10FeSO4 + 8H2SO4 → K2SO4 + 2MnSO4 + 5Fe2(SO4)3 + 8H2O
Which compound is oxidized by KMnO4 in presence of acid in this reaction? Justify.
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Answered by
3
Answer:
F
Explanation:
2 KMnO4 + 10 FeSO4 + 8 H2SO4 → 5 Fe2[SO4]3 + 2 MnSO4 + K2SO4 + 8 H2O
eSO4
This is a complexation reaction: Fe2[SO4]3 is the formed complex.
This is an oxidation-reduction (redox) reaction:
2 MnVII + 10 e- → 2 MnII
(reduction)
10 FeII - 10 e- → 10 FeIII
(oxidation)
KMnO4 is an oxidizing agent, FeSO4 is a reducing agent.
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2KMnO4 + 10FeSO4 + 8H2SO4
K2SO
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