2KMnO4 + Heat → K2MnO4 + MnO2 +___________
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2KMnO4 → K2MnO4 + MnO2 + O2 Given that the molecular mass KMnO4 is 158, what volume. 2KMnO4 → K2MnO4 + MnO2 + O2 Given that the molecular mass KMnO4 is 158, what volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g. of potassium permanganate.
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1
Answer:
2KMnO4 + heat → K2MnO4 + MnO2 + O2
Explanation:
2KMnO4 → K2MnO4 + MnO2 + O2 Given that the molecular mass KMnO4 is 158, what volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g. of potassium permanganate.
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