Question

2l of N2 and 2l of H2 on completion of reaction would give...... l of NH3 at STP

Answer 1

The volume of NH3 is 0.42 L

Explanation:

N2  + 3H2 ----> 2NH3

N

Now calculate the number of moles.

Number of moles = Given volume/ molar volume

No. of moles of hydrogen = 2L/22.4 L  = 0.089 moles

No. of moles of nitrogen = 2L/22.4 L = 0.089 moles

3 moles of H2 combines with 1 mole of N2.

0.089 moles H_2 combines with = 1/3 x 0.089 = 0.029  moles of N2.

H2 is limiting reactant.

3 mole of H2 gives 2 moles of NH3

0.029 moles of H_2 gives= 2/3 x 0.029 = 0.019 moles of NH3

Now 1 mole occupy= 22.4 L

0.019 moles will occupy= 22.4 / 1 x 0.019 = 0.42 L

Thus the volume of NH3 is 0.42 L

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