Question

2log4-log2+2log5 berapakah nilainya

Answer 1

Solution :

2log 4 - log 2 + 2 log5

= log4² - log 2 + log 5²

[ ∵ n log m = log $m^{n}$ ]

= log 16 - log 2 + log 25

= log ( 16/2 ) + log 25

[ ∵ log m - log n = log ( m/n ) ]

= log 8 + log 25

= log ( 8 × 25 )

[ ∵ log m + log n = log ( mn ) ]

= log 200

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