Question

2log5/8+log128/125+log5/2

Answer 1

=$log \frac{5}{8} ^{2} \: + log \frac{128}{125} \: + log \frac{5}{2}$

=$log \frac{25}{64} + log1.024 + log2.5$

=$(log0.390625 \times 1.024 )+ log2.5$

=$log0.4 \times 2.5$

=$log \: 1$

hope it helps you