Math, asked by omairhashmi, 10 months ago

2log5-log2+3log4+1 in terms of log
As a single logarithm

Answers

Answered by sanjoysamaddar
3

Answer:

3(log 2 +1)

Step-by-step explanation:

Log 25-log 2+log 64+log 10

Log 25/2+log 640

Log 25/2 * 640

Log 8000

Log 8 * 1000

Log 8 + log 1000

3log 2 + 3

3(log 2+1)

Answered by kananverma74
7

hey mate here is your answer..

2log5-log2+3log4+1

=log 5²+ log 2+log4³+log10

=log25+log2+log64+log 10

log(25×2×64×10)

log 3200..

thanks ..

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