Question

2m-1/3,3m+1/6,6m+1/2 are the 3 consecutive terms of an arithmetic sequence.Find the value of m
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Answer 1

first term :- 2m-1/3

second term :- 3m+1/6

third term :- 6m+1/2

t1 - 2m-1/3

t2- 3m+1/6

t3- 6m+1/2

(t1)(t2)=(t2)(t3)

2m-1/3×3m+1/6=3m+1/6×6m+1/2

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Answer 2

Answer:

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