Question

(2m+1)x2 +2(m+3)x +(m+5) = 0)​

Answer 1

Answer:

uitiurh

Explanation:

5343135-+5*6/8*-*5+66-84/3+%- 56688*865+58-8*668+8-+6/

*6-6+5*66+8-545433+5+8-*

*3+5+5468+

-66+6789455421684546+-68/668*6+3-5*-++

676453+8/

Answer 2

for equal roots D=b

2

−4ac=0

⇒[2(m+1)]

2

−4m(3m+1)=0

⇒m

2

+2m+1−3m

2

−m=0

⇒−2m

2

+m+1=0

⇒2m

2

−m−1=0⇒(m−1)(m+

2

1

)=0

⇒

m=1,

2

−1