Question

2m(m-4)-8=m(2m-12) solution ​

Answer 1

Answer:

$\Large\boxed{M=2}$

Step-by-step explanation:

GIVEN:

To solve this problem, first you have to isolate by the m from one side of the equation.

SOLUTIONS:

First, you have to expand by using with distributive property.

$\Large\boxed{\textnormal{DISTRIBUTIVE PROPERTY}}}$

$\displaystyle A(B+C)=AB+AC$

2m(m-4)

A=2m

B=m

C=4

$\displaystyle 2mm-2m*4$

$\displaystyle 2mm-2*4m$

Solve.

$\displaystyle 2mm-2*4m=2m^2-8m$

$\displaystyle 2m^2-8m$

Rewrite the problem down.

$\displaystyle 2m^2-8m-8=m(2m-12)$

Expand.

m(2m-12)

A=m

B=2m

C=12

$\displaystyle 2mm-12m$

$\displaystyle 2m^2=2mm$

$\displaystyle 2m^2-12m$

$\displaystyle 2m^2-8m-8=2m^2-12m$

Add by 8 from both sides.

$\displaystyle 2m^2-8m-8+8=2m^2-12m+8$

Solve.

$\displaystyle 2m^2-8m=2m^2-12m+8$

Then, you subtract by 2m²-12m from both sides.

$\displaystyle 2m^2-8m-(2m^2-12m)=2m^2-12m+8-(2m^2-12m)$

Solve.

$\displaystyle 4m=8$

Divide by 4 from both sides.

$\displaystyle \frac{4m}{4}=\frac{8}{4}$

Solve. (Simplify/ to find the answer!)

Divide the numbers from left to right.

$\displaystyle 8\div4=\boxed{2}$

$\Large\boxed{M=2}$

Therefore, the correct answer is m=2.

Answer 2

Solution:

Given,

2m (m - 4) - 8 = m (2m - 12)

or, 2m² - 8m - 8 = 2m² - 12m

[ Multiplying among the terms ]

or, - 8m - 8 = - 12m

[ Subtracting 2m² from both sides ]

or, 12m - 8m = 8

[ Taking different terms on each side ]

or, 4m = 8

[ Doing operation in like terms ]

or, m = 2

[ Dividing both sides by 4 ]

Therefore, the required solution is

m = 2 (Ans.)