Question

2m, m² -1, m² +1 Solve By Pythagorean Triplet​

Answer 1

Answer:

this is Pythagoras theorem formula

Answer 2

Step-by-step explanation:

Pythagorean triplets --- a²-b² = c²

Given terms are 2m, m²-1, m²+1

Now if we take m²-1 as 'a' and 2m as 'b' and m²+1 as 'c'.

Then a²-b² = c²

(m²-1)² + (2m)² = (m²+1)²

(m⁴- 2m²+1) + 4m² = m⁴+2m²+1

m⁴+2m²+1 =m⁴ +2m²+1

Hence, LHS = RHS