Math, asked by jezz132021, 1 month ago

Shabnam travels 9 km towards west and then 6km towards her left. Then, sheturns towards east and travels 2 km. Finally, she travels 5 km towards north. How far is she from the starting point?

a. 5 √3 km

b. 5 km

c. 5 √2 km

d. none

Answers

Answered by kartikdwivedi1009
2

option c. 5√2 km is the correct opinion

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Answered by sourasghotekar123
0

Answer:

c. 5 √2 km

Step-by-step explanation:

TO FIND: The distance far from the starting point by her.

GIVEN:

       

Shabnam travels towards west    9 km

Then towards her left   6km\\

Then, she turns towards east and travels  2 km

she travels  towards north 5 km

By the figure we conclude how far she is from the starting point.

From figure

        AB=9KM\\BC=6KM\\CD=2KM\\DE=5KM\\EF=1KM\\AF=7KM\\AE=?

From pythagoras theorem

Triangle AEF

  AE^{2} =EF^{2}+AF^{2} \\ AE^{2} =(1)^{2} +(7)^{2} \\AE^{2} =50\\AE=\sqrt{50} \\AE=5\sqrt{2} KM

The distance far from the starting point by her =5\sqrt{2} KM

The project code is  #SPJ2

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