( 2n+2 )! = 360 find the value of n( 2n+2 )! = 360 find the value of n ? ?
Answers
Answered by
2
n! / (n-4)! = 360
n (n-1)(n-2)(n-3)(n-4)! / (n-4)! = 360
n (n-1)(n-2)(n-3) = 360
factorise 360 so that 360 can be written in the form of 4 consecutive numbers.
360 = 6×5×4×3
n (n-1)(n-2)(n-3) = 6×5×4×3
compare both L.H.S and R.H.S
therefore, n = 6
n (n-1)(n-2)(n-3)(n-4)! / (n-4)! = 360
n (n-1)(n-2)(n-3) = 360
factorise 360 so that 360 can be written in the form of 4 consecutive numbers.
360 = 6×5×4×3
n (n-1)(n-2)(n-3) = 6×5×4×3
compare both L.H.S and R.H.S
therefore, n = 6
hussainalshajjar:
How you get n!/(n-4)! ?
Answered by
0
2 n + 2 is equal to 360
2 n is equal to 360 -2
2 n is equal to 358
n is equal to 358 by 2
and n is equal to 179
add value of an is 179
2 n is equal to 360 -2
2 n is equal to 358
n is equal to 358 by 2
and n is equal to 179
add value of an is 179
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