Question

^(2n)^(c) 3=11×^n^(c)3​

Answer 1

Answer:

Given

2n

C

3

:

n

C

3

=11:1

⇒

2n

C

3

=11×

n

C

3

⇒

3!

2n(2n−1)(2n−2)

=11×

3!

n(n−1)(n−2)

[∵

n

C

r

=

(n−r)!×r!

n!

]

⇒4(2n−1)=11(n−2)

⇒8n−4=11n−22

⇒11n−8n=22−4

⇒3n=18

⇒n=6

Step-by-step explanation:

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