Question

2n factorial can be written as

Answer 1

Answer:

$(2n)!=[1.3.5................(2n-3)(2n-1)][n!](2^n]$

Step-by-step explanation:

Concept:

The continued product of first n natural number is called n factorial and is denoted by n!

$(2n)!=1.2.3................n.(n+1).(n+2)................(2n-2)(2n-1)(2n)$

$(2n)!=[1.3.5................(2n-3)(2n-1)][2.4.6.....................(2n-2)(2n)]$

$(2n)!=[1.3.5................(2n-3)(2n-1)][(1*2).(2*2).(3*2).....................((n-1)*2)(n*2)]$

$(2n)!=[1.3.5................(2n-3)(2n-1)][1.2.3.....................(n-1).n](2^n)$

$(2n)!=[1.3.5................(2n-3)(2n-1)][n!](2^n]$

Answer 2

Answer:

Step-by-step explanation: