Question

2nC3 : nC2 = 12
Find n?

Answer 1

2nC3/nC2  =  12/1

((2n)!/3!*(2n-3)! )  / n!*2!(n-2)! =12

(2(2n-1)(2n-2) )/3(n-1)  =12

4(2n-1) =36

2n =10

There fore n=5....

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Answer 2

ok here is your answer