Question

2nd one pls 50points I'll mark it as brainliest..wrong ones will be reported..

Answer 1

Here's ur answer

I hope it will help you

Steps...........

1. First draw line QR 8cm

2.Make angle 60°

3. Extended the line , so that DQ 3.5 cm

4. Draw perpendicular line of DR

5. Join that line where it touches the line QX at point P

6. Now, join PR

7. Hence the required triangle is PQR

See the diagram in picture

Answer 2

Here's the step for constriction :-

i) Draw QR = 6 cm.  

ii) Construct  ∠YQR = 60°.  

iii) Produce YQ to Y'  to form line YQY'.

iv) From ray QY'  cut-off line segment QS = 2 cm.  

v) Join SR.  

vi) Draw perpendicular bisector of RS which intersect QY at  P.

vii) Join PR to obtain required DPQR.  

 As P lies on the perpendicular bisector of RS. Therefore, PR = PS = PQ + QS = PQ + 2 cm

 ⇒  PR - PQ = 2cm

Hence, △PQR is the required triangle.