2nd order reaction reactant. How will the rate of reaction be affected if the concentration of this reactant
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Let the reaction is A --> Product
Rate = k[A]2
(I) If conc. of A is doubled
R’ = K[2A]2 = 4K[A]2 = 4R
So rate of reaction will increae four times.
(ii) If conc, of reactants is reduced to half
R’ = K[1/2A]2= 1/4K[A]2= R/4
Rate of reaction will reduced to one fourth of the initial rate.
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