Question

2nd.
question iii and iv one

Answer 1

Answer:

10000

Step-by-step explanation:

iii) $125^{2}-75^{2}$

here we have to ue the formula $a^{2}-b^{2}= (a+b)(a-b)$

=(125+75)(125-75)=200×50=10000

iv) 109×110=(100-1)(100+1)=$100^{2}-1^{2}$

=10000-1=999

hope this ans was helpful

feel free to clear your doubts

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thank you

merry christmas

Answer 2

1). (9.8)^2=(10-0.2)^2
using (a-b)^2 = a^2+ b^2 -2ab
(10)^2 + (0.2)^2 -2(10)(0.2)
100+0.04 -4
96.04

2) if X=300
300-2=298
300+2=302
using (X+a)(x-b)=x^2+(a+b)X -ab
(300)^2+(4)300 -2*2
90000+1200-4
91196

3) 125^2 -75^2
using. a^2 - b^2 = (a+b)(a-b)
(125+75)(125-75)
200*50
10000

4) if X= 100
109=100+9
110=100+10
using (X+a)(x-b)=x^2 (a+b)X - ab
(100)^2 (9+10)100 -9*10
10000 + 1900-90
11810
I hope it will help you.
I want to wish you merry Christmas ☃☃☃☃☃☃