Question

2numbers are in the ratio 4:3. if they differ by 18,find these numbers​

Answer 1

Answer:

GIVEN

Two numbers are in Ratio 4:3

And their Difference is 18

TO FIND :- Those Numbers

SOLUTION

METHOD - 01(by linear equation in one variable)

If both the number are in ratio 4:3

Then Let one number be 4x

The Other will be 3x

Now , According to the Question

4x - 3x = 18

=> x = 18

So, both the numbers are

3x = 3 × 18 = 54

4x = 4 × 18 = 72

Hence the answers are 54 and 72

METHOD - 02(By Linear equation in two variable)

Now,

Let x and y be the numbers

x:y = 4:3

=> x/y = 4/3

=> 3x = 4y ... eq.01

x - y = 18 ...eq.02

Now from eq.01 x = 4y/3

putting in eq. 02,

4y/3 - y = 18

=> (4y - 3y)/3 = 18

=> y/3 = 18

=> y = 54

Now putting this value in eq. 01

3x = 4 × 54

=> x = 216/3

=> x = 72

Hence, the numbers are 72 and 54.(ANS)

Step-by-step explanation:

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Answer 2

Answer:

the two numbers are 54 and 72.

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