Question

50. Two particles are shown in Figure. At t=0,
a constant force F = 6 N starts acting on
the 3 kg man. Find the velocity of the
centre of mass of these particles at t = 5 s.​

Answer 1

Answer:

velocity=15 m/s

i.e.

t=5s

m=3 kg

Answer 2

The velocity of the  centre of mass is 10 m/s .

Given :

Force on object , F = 6 N .

Mass of object , m = 3 kg .

We need to find the velocity at time t = 5 sec .

Also , initial velocity of object , u = 0 m/s .

We know , F = ma

$a=\dfrac{F}{m}\\\\a=\dfrac{6}{3}\\\\a=2\ m/s^2$

We also know , according to equation of motion.

$v=u+at\\\\v=0+2\times 5\\\\v=10\ m/s$

The velocity of the  centre of mass is 10 m/s .

Learn More :

Kinematics

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