Question

2ohm 3 ohm and 5ohm find the total resistance in parallel ​

Answer 1

Here Is Your Ans

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$= > \frac{1}{r} = \frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3} \\ \\ = > \frac{1}{r} = \frac{1}{2} + \frac{1}{3} + \frac{1}{5} \\ \\ = > \frac{1}{r} = \frac{15 + 10 + 6}{30} \\ \\ = > \frac{1}{r} = \frac{31}{30} \\ \\ = > r = \frac{30}{31} \\ \\ = > 0.967741935 \: \: ohm$

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Answer 2

Let R1,R2 and R3 be the given resistances of the conductors.

R1=2Ω,R2=3Ω and R3=5Ω

From the question,

The resistors are connected in parallel.

Let Rp denote the total resistance of the three resistors.

$\frac{1}{ rp}= \frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3} \\ \\ \implies \: \frac{1 }{rp} = \frac{1}{2} + \frac{1}{3} + \frac{1}{5} \\ \\ \implies \: \frac{1}{rp} = \frac{15 + 6 + 10}{30} = \frac{31}{30} \\ \\ \implies \: \frac{1}{rp} = \frac{31}{30} \\ \\ \implies \: \huge \boxed{ \boxed{rp = \frac{30}{31}Ω}}$

The equivalent resistance is 30/31Ω