(2p^2/q^2+5q^2/p^2)(2p^2/q^2-5q^2/p^2)
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Answered by
0
Answer:
Answer
Let f(x)=3x
−
5x−2 roots p,qp+q=5/3pq=−2/3
Equation whose roots are 3p−2q & 3q−2p
x
2
−(3p−2q+3q−2p)x+(3p−2q)(3q−2p)=0
x
2
−(p+q)x+(9pq−6p
2
−6p
2
−6q
2
+4pq)=0
x
2
−(p+q)x+(13pq−6(p
2
+q
2
))=0
x
2
−(p+q)x+(13pq∗6((p
2
+q
2
)−2pq))=0
x
2
−(p+q)x+(13pq−6(p+a)
2
+12pq)=0
x
2
−(p+a)x+(25pq−6(p+q)
2
)=0
x
2
−
3
5x
+(25(
3
−2
−6(
3
5
)
2
))=0
x
2
−
3
5x
+(−
3
50
−
9
150
)=0
x
2
−
3
5x
+(−
3
50
−
3
50
)=0
3x
2
−5x−100=0
pls follow
Answered by
0
Step-by-step explanation:
bp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10bp=bq=3
and pa=ra=4
rc=ac-ra
rc= 11 - 3
rc = 7
qc = rc = 7
qc + bq = 3 + 7 = 10
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