Question

2p^2q^2- 3pq + 4, 5 + 7pq - 3p2^q^2,4p2^q^2 + 10pq

Answer 1

$2 {p}^{2} {q}^{2} - 3pq + 4 + (5 + 7pq - 3 {p}^{2} {q}^{2} ) \\ +( 4 {p}^{2} {q}^{2} + 10pq) \\ \\ 2 {p}^{2} {q}^{2} - 3pq + 4 + 5 + 7pq - 3 {p}^{2} \\ + 4 {p}^{2} {q}^{2} + 10pq\\ \\ 2 {p}^{2} {q}^{2} + 4 {p}^{2} {q}^{2} - 3pq + 7pq + \\ 10pq - 3 {p}^{2} + 9 \\ \\ 6 {p}^{2} {q}^{2} + 14pq - 3 {p}^{2} + 9$

Answer 2

$\Large\color{red}{\textbf{\textsf{Answer:}}}$

$\tt (2p^{2}{q}^{2} - 3pq + 4) + (5 + 7pq - {3p}^{2} {q}^{2} ) + ( {4p}^{2} {q}^{2} + 10pq) \\ \tt : \implies 2p^{2}{q}^{2} - 3pq + 4 + 5 + 7pq - {3p}^{2} {q}^{2} +{4p}^{2} {q}^{2} + 10pq ~~~~~~~~~~~~\\ \bf Collecting \: the \: like \: terms \: we \: get: ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \\ \tt : \implies (2 {p}^{2} {q}^{2} - {3p}^{2} {q}^{2} + 4 {p}^{2} {q}^{2} ) + ( - 3pq + 7pq + 10pq) + (4 + 5) \\ \tt : \implies \color{red}{ \underline{ \boxed{ \bf 3 {p}^{2} {q}^{2} + 14pq + 9}}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~$