Math, asked by pritamshah0125, 10 months ago

2p+3q=13
5p-4q=-2
please solve this ​

Answers

Answered by NaVila11
1

Elimination method

Given:

2p + 3q =13 -------- (1)

5p - 4 q = -2---------(2)

Now;

(1)* 5 = 10p + 15 q = 65

(2)*2 = 10p - 8 q. = - 4

(-) (+) (+)

-----------------------------------

= 23q = 69

= q = 69/23

= q =3

Now putting the value of q in equation (1)

we get;

2p + 3q = 13

2p + 3(3) = 13

2p + 9 = 13

2p = 13-9

p = 4/2

p= 2

Substitution Method

Given :

2p+3q=13-------(1)

2p=13-3q

p=13-3q/2-------(2)

5p-4q=-2-------(3)

sub (2)in (3)

5(13-3q/2)-4q=-2

65-15q/2-4q=-2

65-15q-8q=-4

-23q=-69

q=3

Then substitute the value of q in equation (I) and find the value of p

2p + 3q = 13

2p + 3(3)= 13

2p + 9= 13

2p = 13 - 9

2p = 4

p= 4/ 2

p=2

U can do it by any one method.....

Hope this helps u

plz don't forget to mark it as brainliest

Thank you

Regards

NaVila11

#followpls#

Similar questions