2p+3q=13
5p-4q=-2
please solve this
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Elimination method
Given:
2p + 3q =13 -------- (1)
5p - 4 q = -2---------(2)
Now;
(1)* 5 = 10p + 15 q = 65
(2)*2 = 10p - 8 q. = - 4
(-) (+) (+)
-----------------------------------
= 23q = 69
= q = 69/23
= q =3
Now putting the value of q in equation (1)
we get;
2p + 3q = 13
2p + 3(3) = 13
2p + 9 = 13
2p = 13-9
p = 4/2
p= 2
Substitution Method
Given :
2p+3q=13-------(1)
2p=13-3q
p=13-3q/2-------(2)
5p-4q=-2-------(3)
sub (2)in (3)
5(13-3q/2)-4q=-2
65-15q/2-4q=-2
65-15q-8q=-4
-23q=-69
q=3
Then substitute the value of q in equation (I) and find the value of p
2p + 3q = 13
2p + 3(3)= 13
2p + 9= 13
2p = 13 - 9
2p = 4
p= 4/ 2
p=2
U can do it by any one method.....
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NaVila11
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