Question

2p²{(3q-p)-(2q+3p)}-{3q³+2p³)​

Answer 1

$2p^{2} (3q-p)-(2q+3p)-(3p^{3}+2p^{3} )$

=$6p^{2}q-2p^{3}-4p^{2}q+6p^{3}-6p^{2}qx^{3}+4px^{5}$

=$6p^{2}q-4p^{3}-4p^{2}q-6p^{2}qx^{3}+4px^{5}$ ANS