Question

2root 2x cube +3root3 cube factorise​

Answer 1

Answer:

The answer is -

Step-by-step explanation:

To factorize 2$\sqrt{2}$$x^{3}$ + 3$\sqrt{3}$$x^{3}$

Follow the identity

= $(\sqrt{2}x)^{3}$ + $(\sqrt{3}x)^{3}$[Using identity $a^{3}$ + $b^{3}$ = (a + b)($a^{2}$ - ab + $b^{2}$)]

= ($\sqrt{2}x$ + $\sqrt{3}x$)[$(\sqrt{2}x)^{2}$ - ($\sqrt{2}x$)($\sqrt{3}x$) + $(\sqrt{3}x)^{2}$]

= ($\sqrt{2}x$ + $\sqrt{3}x$)(2$x^{2}$ - $\sqrt{6} x^{2}$ + 3$x^{2}$)

= ($\sqrt{2}x$ + $\sqrt{3}x$)(5$x^{2}$ - $\sqrt{6} x^{2}$)