Question

2sin=1,then the value of (3cot2+3)will be​

Answer 1

Step-by-step explanation:

$2\sin( \alpha ) = 1$

$\sin( \alpha ) = 1 \div 2$

$but\sin(30) = 1 \div 2$

$therefore \: ( \alpha ) = {30}^{0}$

$\cot(60) = 1 \div \sqrt{3}$

$3 \cot(2 \alpha ) = 3 \times 1 \div \sqrt{3 }$

$therefore \: 3 \cot(2 \alpha ) = \sqrt{3}$

$3 \cot(2 \alpha ) \ + 3 = \sqrt{3} + 3$