Question

2sin^2(3π/4)+2cos^2(π/4) +2sec^2(π/3)=10​

Answer 1

Answer:

2sin^2 3π/4 +2cos^2 π/4 + 2sec^2 π/3

=2 sin^2 3*180/4 +2 cos^2 180/4 +2 sec^2 2*180/3

= 2 sin ^2 3*45+2 cos^2 45 + 2 sec^ 120

= 2 sin^ 135 + 2{ 1/\sqrt{2}

2

}^2 +2 (- sec 60 )^2

= 2 (cos 45)^2+2*1/2+ 2 *2^2

=2 *{1/\sqrt{2}1/

2

}^2 +1+8

= 2*1/2+1+8

= 1+9

= 10

Answer 2

Answer:

in this question you have to check the trigonometric ratio table for the value of

sin cos and sec

after putting value and simplify the question you will get LHS= RHS

hope this helps you!!!

thankyou!!