2sin^2A-cos^2A=2,then find the value of A
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sin ^2 A = 1 - cos ^2 A
2 sin ^2 A - cos ^2 A = 2
2 - 2 cos ^2 A - cos ^2 A = 2
2 - 3 cos ^2 A = 2
3 cos ^2 A = 0
cos ^2 A =0
2 sin ^2 A - cos ^2 A = 2
2 - 2 cos ^2 A - cos ^2 A = 2
2 - 3 cos ^2 A = 2
3 cos ^2 A = 0
cos ^2 A =0
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