Question

2sin²3π/4 + 2 cos²π/4 + 2 sec²π/3=10​

Answer 1

Answer:

2sin²3π/4 =2x(1/√2)² = 1

2cos²π/4=2x(1/√2)²=1

2sec²π/3=2x4=8

:. 2sin²3π/4+2cos²π/4+2sec²π/3=1+1+8=10

Hence,proved

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