Question

2sin²30°-2cos²45°+tan²60°​

Answer 1

Step-by-step explanation:2(1/2)^2- 2(1/√2)^2+ √3^2 =2(1/4)- 2(1/4)+ 3 =2/4- 2/4 + 3 =2-2+3 =2-5=-3

Answer 2

The answer of this question is $\frac{5}{2}$.

Step-by-step explanation:

We are given,

$2*(Sin)^{2} 30\°-2*(Cos)^{2}45\°+(tan)^{2}60\°$

and we have to find he value of this trigonometric equation.

• Trigonometric values used,

1. $Sin30\°=\frac{1}{2}$
2. $Cos45\°=\frac{1}{\sqrt{2} }$
3. $Tan60\°=\sqrt{3}$

• Solving given trigonometric equation

We have

$2*(Sin)^{2} 30\°-2*(Cos)^{2}45\°+(tan)^{2}60\°$

and we have the values of required trigonometric ratios,

$Sin30\°=\frac{1}{2}$   , $Cos45\°=\frac{1}{\sqrt{2} }$   and $Tan60\°=\sqrt{3}$.

by simply putting the values we get our answer,

$2*(\frac{1}{2} )^{2} -2*(\frac{1}{\sqrt{2} } )^{2} +(\sqrt{3} )^{2}$

$2*\frac{1}{4} -2*\frac{1}{2}+3$

   $=\frac{1}{2} -1+3$

    $= \frac{1}{2}+2$

    $=\frac{1+4}{2}$

     $=\frac{5}{2}$

In this way we get the answer of this question as $\frac{5}{2}$.