Question

2sin²x+3cosx=0
solve this question plz​

Answer 1

Step-by-step explanation:

Given Equation is 2sin²x + 3cosx = 0

⇒ 2(1 - cos²x) + 3cosx = 0

⇒ 2 - 2cos²x + 3cosx = 0

⇒ 2cos²x - 3cosx - 2 = 0

⇒ 2cos²x - 4cosx + cosx - 2 = 0

⇒ 2cosx(cosx - 2) + (cosx - 2) = 0

⇒ (2cosx + 1)(cosx - 2) = 0

⇒ cosx - 1/2, cosx = 2[Not possible]

⇒ cosx = -1/2

⇒ x = 120°,240°

⇒ x = (2π/3) + 2πn, x = (4π/3) + 2πn

Hope it helps!

Answer 2

Answer:

Step-by-step explanation:

See the attachment please..!!

Hope you will get a better solution.

We will just simply tern in cos terms!

Check the attachment !!

Cos periodic function with 2pie!!