Question

2sin2x+root3cosx+1=0
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Answer 1

Answer:

I don't know the answer

Answer 2

2sin2x +root3cos x +1 =0

2-2cos2x+root 3 cos x + 1=0

-2cos2x +root 3 cos x +3 = 0

Sum = root 3

Prdct= -6

-2 cos2x +2 root 3 cos x- root 3 cos x+ 3 =0

-2cosx(cosx - root 3) - root 3 (cos x- root 3 )=0

(cosx - root 3)( -2cosx- root 3 )=0

Cos x = root 3

(not possible)

Therefore x =cos -1[root 3]

(cos inverse root 3 )

Cosx= (root 3)/2

Cos π/6 =( root 3)/2

Cos x =cos y

Therefore x=2nπ±π/6

hope it will help you.

hope it will help you.plss brainliest my answer.