2sin5π/12sinπ/12=1/2
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Answered by
42
Hey !!!
From LHS
2sin5π/12 sinπ/12
=> 2sin(π/2 - π/12 ) ×sinπ/12
=> sin(π/2-π/12) ×sinπ/12
=> 2cosπ/12 ×sinπ/12
•°• 2sinA×cosA= sin2A
like that ..
=> sin 2× 180°/12
=> sin360/12
=> sin30°
=> 1/2 Hence RHS prooved
******,,,,,,,,********************
Hope it helps you !!!
@Rajukumar111
From LHS
2sin5π/12 sinπ/12
=> 2sin(π/2 - π/12 ) ×sinπ/12
=> sin(π/2-π/12) ×sinπ/12
=> 2cosπ/12 ×sinπ/12
•°• 2sinA×cosA= sin2A
like that ..
=> sin 2× 180°/12
=> sin360/12
=> sin30°
=> 1/2 Hence RHS prooved
******,,,,,,,,********************
Hope it helps you !!!
@Rajukumar111
rohitkumargupta:
bro sin2A = 2sinAcosA
Answered by
54
HELLO DEAR,
we know that:-
2sinx siny = cos (x - y) - cos(x - y).
NOW use the formula here,
2sin5π/12 sinπ/12
=> cos(5π/12 - π/12) - cos(5π/12 + π/12)
=> cos4π/12 - cos6π/12
=> cosπ/3 - cos π/2
[ cosπ/3 = 1/2 , cosπ/2 = 0 ]
=> 1/2 - 0 = 1/2
I HOPE ITS HELP YOU DEAR,
THANKS
we know that:-
2sinx siny = cos (x - y) - cos(x - y).
NOW use the formula here,
2sin5π/12 sinπ/12
=> cos(5π/12 - π/12) - cos(5π/12 + π/12)
=> cos4π/12 - cos6π/12
=> cosπ/3 - cos π/2
[ cosπ/3 = 1/2 , cosπ/2 = 0 ]
=> 1/2 - 0 = 1/2
I HOPE ITS HELP YOU DEAR,
THANKS
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