Math, asked by divs007, 1 year ago

(2sin5x.cosx)(2cos5x.sinx)

Answers

Answered by chopraneetu
8
2sin5x.cosx.2cos5x.sinx
=(2sin5x.cos5x)(2sinx.cosx)
=sin(2×5x)sin (2×x)
=sin10xsin2x

hafeezhtech: in your second step how did you get (2sinx.cosx)
chopraneetu: just rearranged
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