2sinAcosA-cos A/1-sinA+sin*2A-cos2A
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Answer:
(2sinA.cosA-cosA)/(1-sinA+sin^2A-cos^2A) = cot A.
L.H.S.
= cosA.(2sinA-1)/{(1-cos^2A)+sin^2A-sinA}. , putting 1-cos^2A = sin^2A.
= cosA.(2sinA-1)/{sin^2A+sin^2A-sinA}.
= cosA.(2.sinA-1)/{2.sin^2A-sinA}.
= cosA.(2sinA-1)/sinA.(2.sinA-1).
= cosA/sinA.
= cotA. Proved
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