Math, asked by Nishthaakukreja40641, 10 months ago

2sinAsinB is equal to

A) sin(A+B) + sin(A­-B) B) cos(A-­B) -­ cos(A+B) C) sin(A+B) -­ sin(A-­B) D) cos(A+B) + cos(A-­B)

Answers

Answered by psquare710
0

Answer:

B ) cos (A-B) -cos (A+B)

cos A .cos .B +SinA.sin B -{ cos A .cosB -sin A .sin B )

2 sin A .sin B

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