2sinQcosQ-cosQ/1-sinQ+sin^2Q-cos^Q=?
pls guys answer this immediately.First answer would be chosen as BRAINLIEST(but it should be correct one)....
here Q is theta.
Answers
Answered by
0
Answer on cross multiplying
2-sinQ.cosQ-cosQ=cotQ-cosQ+2cos^Q-cos2Q.cotQ
=2-sinQ.cosQ=cotQ[1-cos2Q]+2cos^Q=cotQ [2sin^Q] +2cos^Q
=2-sinQcosQ
=2sinQcosQ+2Cos^Q
=2-2cos^Q
=3sinQcosQ
=2[sin^Q]
=3sinQcosQ
=2sinQ
=3cosQtanQ
=3/2
Therefore sinQ=3/√13CosQ=2/√13
hope it will help u
Answered by
3
Step-by-step explanation
2sinQcosQ-cosQ/1-sinQ+sinQ^2-cos^2Q
2sinQcosQ-cosQ/1-sinQ-(sin^2Q+cos^2Q)
2sinQcosQ-CosQ/1-sinQ-1
2sinQcosQ/-sinQ -cosQ/-sinQ
=-2cosQ+cotQ
Hope it helps...
Pl mark it as brainiest...
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