Question

2t + 11 /4 = 1 /3 t + 2​

Answer 1

As per the data given in the question,

We have to determine the value of "t" in the above given expression.

As per question,

It is given that,

$2t + \frac{11}{4} = \frac{1}{3}t + 2$

So, for solving the given expression, we will solve the given equation by separating the like terms on one side.

$2t -\frac{1}{3}t = 2- \frac{11}{4}\\=>\frac{6t-t}{3} = \frac{8-11}{4}\\=>\frac{5t}{3} = \frac{-3}{4}\\=>5t = - \frac{9}{4}\\=>t = -\frac{9}{4\times 5}\\=>t = -\frac{9}{20}$

Hence, value of "t' in the above given expression $2t + \frac{11}{4} = \frac{1}{3}t + 2$ will be $-\frac{9}{20}$

Answer 2

Answer:

The value of t is 0.45 or $\frac{-9}{20}$

Step-by-step explanation:

Given -

$2t + \frac{11}{4} = \frac{1}{3} t + 2$

To Find -

The value t

Solution -

given equation,

$2t + \frac{11}{4} = \frac{1}{3} t + 2$

Shift 1/3 to left and 11/4 to right  we get

$2t -\frac{1}{3} t = 2-\frac{11}{4}$

For Subtracting fraction number both the fraction of denominator should be same.

Multiply 2 by $\frac{3}{3}$ and right side 2 by $\frac{4}{4}$ we get

$\frac{6}{3} t -\frac{1}{3} t = \frac{8}{4} -\frac{11}{4}$

$\frac{6-1}{3} t=\frac{8-11}{4}$

$\frac{5}{3}t = \frac{-3}{4}$

shift 5/3 to right it becomes 3/5

$t = \frac{-3}{4}\times \frac{3}{5}$

$t= \frac{(-3)\times 3}{4 \times 5} \\t = \frac{-9}{20}$

In fraction converted into decimal.

$t = 0.45$

The value of t is 0.45 or $\frac{-9}{20}$